Question

(Sinx-1/2)(Sinx+1)=0

Answer 1

$(sinx- \frac{1}{2} )(sinx+1)=0 \\sinx- \frac{1}{2}=0 \\sinx= \frac{1}{2} \\x_1= \frac{\pi}{6} +2\pi n,\ n \in Z \\x_2= \frac{5\pi}{6} +2\pi n,\ n \in Z \\sinx+1=0 \\sinx=-1 \\x_3=- \frac{\pi}{2} +2\pi n,\ n \in Z$