Question

(х+2) в 4 степени-5(х+2)²+4=0
Помогите пожалуйста

Answer 1

( x + 2 )^4 - 5( x + 2 )^2 + 4 = 0
( x + 2 )^2 = a ; a > 0
a^2 - 5a + 4 = 0
D = 25 - 16 = 9 = 3^2 
a1 = ( 5 + 3 ) : 2 = 4 
a2 = ( 5 - 3 ) : 2 = 1 
( x + 2 )^2 = 4 
x^2 + 4x + 4 = 4 
x( x + 4 ) = 0 
x1 = 0
x2 = - 4 
( x + 2 )^2 = 1 
x^2 + 4x + 4 - 1 = 0
x^2 + 4x + 3 = 0
D = 16 - 12 = 4 = 2^2 
x1 = ( - 4 + 2 ) : 2 = - 1 
x2 = ( - 4 - 2 ) : 2 = - 3 
Ответ    ( - 4 ) ;  ( - 3 ) ; ( - 1 ) ; 0