Question

B4 пожалуйста!!! 40б

Answer 1

$\frac{1}{x} = \frac{x}{2x+1} \\x \neq 0\\x \neq - \frac{1}{2} \\2x+1=x^2\\x^2-2x-1=0\\D_1=1+1=2\\x_1=1+ \sqrt{2} \\x_2=1- \sqrt{2} \\x_1^2+x_2^2\\(1+ \sqrt{2})^2+(1- \sqrt{2})^2=1+2 \sqrt{2}+2+1-2 \sqrt{2} +2=1+2+1+2=\\=6$