Question

dx/√4x+5 найти интеграл

Answer 1

$\LARGE \\ \int{\mathrm{dx}\over\sqrt{4x+5}}=\begin{vmatrix} 4x+5=t^2\\ \mathrm{dx}={t\mathrm{dt}\over2} \end{vmatrix}={1\over2}\int{t\mathrm{dt}\over\sqrt{t^2}}={1\over2}t+C={1\over2}\sqrt{4x+5}+C$