Question

Помогите 2 задание ( х(2) - 25) и т.д

Answer 1

(х²-25)/(12х+22) * (3/(х-5) + 4х/(х²-3х-10) - 1/(х+2)) = 
= (х²-25)/(12х+22) * (3(х+2)/(х²-3х-10) + 4х/(х²-3х-10) - (х-5)/(х²-3х-10)) = 
= (х²-25)/(12х+22) * (3х+6 + 4х - х+5)/(х²-3х-10) = 
= (х²-25)/(12х+22) * (6х+11)/(х²-3х-10) = 
= (х-5)(х+5)/2(6х+11) * (6х+11)/(х-5)(х+2) = 
= (х+5)/2(х+2)   или  (х+5)/(2х+4)