Question

x2-12=0 x1=12 x2=0 Это правельно ?

Answer 1

${x}^{2} - 12 = 0 \\ {x}^{2} = 12 \\ x = + - \sqrt{12} \\ x1 = \sqrt{12} = 2 \sqrt{3} \\ x2 = - \sqrt{12} = - 2 \sqrt{3}$