Question

помогите пожалуйста номер 1134

Answer 1

1)
$\frac{ \frac{2}{15} }{ \frac{1}{5} x - \frac{1}{3} } - \frac{1}{12} = \frac{1}{24} \\ \frac{ \frac{2}{15} }{ \frac{1}{5} x - \frac{1}{3} } = \frac{1}{24} + \frac{1}{12} \\ \frac{ \frac{2}{15} }{ \frac{1}{5} x - \frac{1}{3} } = \frac{3}{24} \\ \frac{ \frac{2}{15} }{ \frac{1}{5} x - \frac{1}{3} } = \frac{1}{8} \\ \frac{1}{5} x - \frac{1}{3} = \frac{2}{15} \div \frac{1}{8} \\ \frac{1}{5} x - \frac{1}{3} = \frac{16}{15} \\ \frac{1}{5} x = \frac{1}{3} + \frac{16}{15} \\ \frac{1}{5} x = \frac{21}{15} \\ x = \frac{21}{15} \div \frac{1}{5} \\ x = \frac{21}{15} \times \frac{5}{1} \\ x = 7$

2)
$\frac{ \frac{2}{9} }{ \frac{5}{9} x - \frac{1}{2} } + \frac{1}{7} = \frac{1}{3} \\ \frac{ \frac{2}{9} }{ \frac{5}{9} x - \frac{1}{2} } = \frac{1}{3} - \frac{1}{7} \\ \frac{ \frac{2}{9} }{ \frac{5}{9} x - \frac{1}{2} } = \frac{7 - 3}{21} \\ \frac{ \frac{2}{9} }{ \frac{5}{9} x - \frac{1}{2} } = \frac{4}{21} \\ \frac{5}{9} x - \frac{1}{2} = \frac{2}{9} \div \frac{4}{21} \\ \frac{5}{9} x - \frac{1}{2} = \frac{2}{9} \times \frac{21}{4} \\ \frac{5}{9} x - \frac{1}{2} = \frac{7}{6} \\ \frac{5}{9} x = \frac{1}{2} + \frac{7}{6} \\ \frac{5}{9} x = \frac{3 + 7}{6} \\ \frac{5}{9} x = \frac{10}{6} \\ x = \frac{10}{6} \div \frac{5}{9} \\ x = \frac{10}{6} \times \frac{9}{5} \\ x = 3$