Question

Решите систему уравнений

Answer 1

x=$\frac{352}{y}$
($\frac{352}{y}$ -2 ) (y+4)=400

$\frac{14088}{y}$ -2y+344=400

Answer 2

$x = \frac{352}{y} \\ (\frac{352}{y} - 2)(y + 4) = 400 \\ \frac{(352 - 2y)(y + 4)}{y} = 400 \\ 352y + 1408 - 2 {y}^{2} - 8y - 400y = 0 \\ - 2 {y}^{2} - 56y + 1408 = 0 \\ {y}^{2} + 28y - 704 = 0 \\ d = 784 - 4 \times ( - 704) = 3600 \\ y_{1} = \frac{ - 28 - 60}{2} = - 44 \\ y_{2} = \frac{ - 28 + 60}{2} =16 \\ x_{1} = \frac{352}{ - 44} = - 8 \\ x_{2} = \frac{352}{ 16} =22$

Ответ: (-8; -44), (22; 16)