Question

2целых 1/6 + (х+1целая 1/12) = 4целых 3/4

Answer 1

2$\frac{1}{6}$ + ( x + 1$\frac{1}{12}$ ) = 4$\frac{3}{4}$
x + 1$\frac{1}{12}$ = 4$\frac{3}{4}$ - 2$\frac{1}{6}$
x + 1$\frac{1}{12}$ = 4$\frac{9}{12}$ - 2$\frac{2}{12}$
x + 1$\frac{1}{12}$ = $\frac{57}{12}$ - $\frac{26}{12}$
x + 1$\frac{1}{12}$ = $\frac{31}{12}$
x = $\frac{31}{12}$ - 1$\frac{1}{12}$
x = $\frac{31}{12}$ - $\frac{13}{12}$
x = $\frac{31}{12}$
x = $\frac{18}{12}$
x = 1$\frac{6}{12}$
x = 1$\frac{1}{2}$ = 1,5