Question

Решите уравнение: (3 x−5)(2 x+7) = (3 x+1)(2 x−3)+4x

Answer 1

(3 x−5)(2 x+7) = (3 x+1)(2 x−3)+4x
6x² + 21x - 10x - 35 = 6x² - 9x + 2x - 3 + 4x
6x² + 11x - 35 = 6x² - 3x - 3
6x² + 11x - 35 - 6x² + 3x + 3 = 0
14x - 32 = 0
14x = 32
7x = 16
x = $\frac{16}{7}$ = 2$\frac{2}{7}$

Answer 2

(3x−5)(2x+7)=(3x+1)(2x−3)+4x
$6x^{2}+21x-10x-35=6x^{2}-9x+2x-3+4x$
$6x^{2}+11x-35=6x^{2}-3x-3$
$6x^{2}+11x-6x^{2}+3x=-3+35$
$14x=32$
$x=32:14$
$x=\frac{32}{14}=\frac{16}{7}=2\frac{2}{7}$