Question

найдите производную функции f(x)=sin²x-sinx+5

Answer 1

$f(x)=sin^2x-sinx+5 \\ \\ f'(x)=(sin^2x)'-(sinx)'+(5)' = \\ \\ = 2sinx *(sinx)' - cosx + 0 = \\ \\ = 2sinx *cosx - cosx = sin2x - cosx$