Question

(n-2)! / (n-4)! (n-3)

Answer 1

$\frac{(n-2)!}{(n-4)!(n-3)} = \frac{(n-2)(n-3)(n-4)!}{(n-4)!(n-3)} = \frac{(n-2)(n-3)}{n-3} =n-2$