Question

Найдите производное
У(х) =х^2*2^х

Answer 1

$y(x)=x^2\cdot2^x\\\\y'=(x^2)'\cdot2^x+x^2\cdot(2^x)'=2x\cdot2^x+x^2\cdot2^x\cdot\ln2=\boxed{x\cdot2^x(2+x\ln2)}$

Answer 2

y`=(x²)`*2^x+x²*(2^x)`=2x*2^x+x²*2^x*ln2=x*2^x*(2+xln2)