Question

Решите пожалуйста log0,5(3-2x)>1

Answer 1

$log_{0.5} (3-2x)\ \textgreater \ 1 \\\\ 3-2x\ \textgreater \ 0 \\\\ x\ \textless \ 1.5 \\\\ x\in(-\infty;1.5)\\\\ log_{0.5} (3-2x) \ \textgreater \ log_{0.5} 0.5 \\\\ 3-2x\ \textless \ 0.5 \\\\ -2x\ \textless \ -2.5 \\\\ x\ \textgreater \ 1.25 \\\\ x\in(1.25;1.5)$

Answer 2

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