Question

4/9а²-2ав+9/4в² разложить по ФСУ

Answer 1

$a^2-2ab+b^2=(a-b)^2\\\\\displaystyle \frac{4}9a^2-2ab+\frac{9}4b^2=\bigg(\frac{2}3a\bigg)^2-2ab+\bigg(\frac{3}2b\bigg)^2=\boxed{\bigg(\frac{2}3a-\frac{3}2b\bigg)^2}$