Question

log4(x+1)-log 4(1-x)=log4(2x+3)

Answer 1

log4( x+1/1-x)=log4(2x+3)
X+1/1-x = 2x+3
X+1=(2x+3)*(1-x)
X+1-(2x+3)*(1-x)=0
X+1-(2x-2x^2 +3-3x)=0
X+1-(-x-2x^2 +3)=0
X+1+x+2x^2 -3=0
2x-2+2x^2=0
2(x-1+x^2)=0
X-1+x^2 =0
X^2 +x-1=0
И дальше по фоткам