Question

3x^2+2x=0
7x^2+6x-1=0
2x^2-^18=0
2x^2-x+11=0
Хелп,я аут,срочно

Answer 1

$3 {x}^{2} + 2x = 0 \ x(3x + 2) = 0 \ x = 0 \ x = frac{ - 2}{3} \ \ 7 {x}^{2} + 6x - 1 = 0 \ d1 = {k}^{2} - ac = 9 + 7 = 16 \ x1 = frac{ - k + sqrt{d1} }{a} = frac{ - 3 + 4}{7} = frac{1}{7} \ x2 = frac{ - k - sqrt{d1} }{a} = - 1 \ \ 2 {x}^{2} - 18 = 0 \ {x}^{2} = frac{18}{2} \ {x}^{2} = 9 \ x1 = 3 \ x2 = - 3 \ \ 2 {x}^{2} - x + 11 = 0 \ d = {b}^{2} - 4ac = 1 - 4 times 2 times 11 < 0$
Корней нет

Answer 2

Ты уверен?)

Answer 3

да