Question

Решить уравнения

ctg x= -1/√3

cos x/3= -1

tg( (x )/3+ π)+ √(3 ) = 0

Answer 1

$1)ctgx=- frac{1}{sqrt{3}} \tgx=-sqrt{3} \x= -frac{pi}{3} +pi n, n in Z \2)cos( frac{x}{3})=-1 \ frac{x}{3} =pi+2pi n \x=3pi+6pi n, n in Z \3)tg( frac{x}{3} +pi)=-sqrt{3} \frac{x}{3} +pi=-frac{pi}{3} +pi n \ frac{x}{3} =- frac{4pi}{3} +pi n \x=-4pi+3pi n, n in Z$