Question

Выполните действие:$frac{3}{3x+3y}- frac{1}{x^{2}-y }$

Answer 1

Решение:
$frac{3}{3x+3y}-frac{1}{x^2-y}=frac{1}{x+y}-frac{1}{x^2-y}=frac{x^2-y-x-y}{(x+y)(x^2-y)}=frac{x^2-2y-x}{(x+y)(x^2-y)}$

Answer 2

$frac{3}{3x+3y}-frac{1}{x^{2}-y}=frac{3}{3(x+y)}-frac{1}{x^{2}-y}=frac{1}{x+y}-frac{1}{x^{2}-y}=\ =frac{x^{2}-y-x-y}{(x+y)(x^{2}-y)}=frac{x^2-x-2y}{(x+y)(x^{2}-y)}$