Question

Упростить. Срочно!!!

Answer 1

$(b^{ sqrt{3}+1 }) cdot cfrac{1}{b^{4+ sqrt{3} }} =cfrac{b^{ sqrt{3}+1 }}{b^{4+ sqrt{3} }}= cfrac{b^{ sqrt{3}} cdot b }{b^{4} cdot b^{ sqrt{3}} }}= cfrac{b}{b^4}= cfrac{1}{b^3}$