Question

1,2(b+1,2)+(0,5-b)(b+0,5)-(b+1,3)(1,3-b) при b= - 5/6

Answer 1

1,2(b+1,2)+(0,5-b)(b+0,5)-(b+1,3)(1,3-b)=1,2b+1,44+(0,5-b)(0,5+b)-(1,3+b)(1,3-b)=1,2b+1,44+0,5b^2-b^2-(1,3^2-b^2)=1,2b+1,44+0,5^2-b^2-((13/10)^2-b^2)=1,2b+1,44+0,5^2-b^2-(13/10)^2+b^2=1,2b+36/25+(1/2)^2-169/100=1,2b+36/25+1/4-169/100=1,2b+0=1,2b

1,2b=1,2*(-5/6)=-1