Question

log5(3x+4)=1/2

Answer 1

1/2 = log5($sqrt{5}$)
ОДЗ: 3x+4>0, x> -4/3
log5(3x+4) = log5($sqrt{5}$
3x+4 = $sqrt{5}$
3x=$sqrt{5}$ - 4
x = $sqrt{5}$/3 - 4/3