Question

Буду признателен за помощь :)

Answer 1

$frac{sin^4x+cos^4x+2cos^2xsin^2x}{2cos^2x-2sin^2x+2sin^2x} = frac{(cos^2x+sin^2x)^2}{2cos^2x} = frac{1}{2cos^2 frac{ pi }{3} } = frac{1}{2* frac{1}{4} } =2$