Предмет: Алгебра, автор: valeri2611

Дан график функции y=kx+b. Укажите k

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Автор ответа: dtnth

из графика видим, что прямой принадлежат точки
(-2;0) и (0;3)

$y=kx+b$
$k*(-2)+b=0$
$k*0+b=3$

$-2k+b=0; b=3$
$-2k+3=0; b=3$
$-2k=-3; b=3$
$k=-3:(-2);b=3$
$k=1.5; b=3$
$y=1.5x+3$

ответ: k=1.5

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