Question

СРОЧНО!!!"""""****заранее благодарен

Answer 1

1)$lim_{x to infty} frac{x^2+3x-4}{x^3-4x} = lim_{x to infty} frac{x^2}{x^3}* frac{1+ frac{3}{x}- frac{1}{x^2} }{1- frac{4}{x^2} } =[tex] lim_{x to infty} frac{1}{x} =0.$
2)  $lim_{x to infty} frac{2x-3}{8x-5} = lim_{x to infty} frac{x}{x} * frac{2- frac{3}{x} }{8- frac{5}{x} } = frac{2}8} = frac{1}{4}.$