Question

теңдеуді шеш log3(7x-7)=3

Answer 1

$log_3 (7x-7)=3$
$7x-7>0$
$x-1>0$
$x>1$

$7x-7=3^3$
$7x-7=27$
$7x=27+7$
$7x=34$
$x=frac{34}{7}$