Предмет: Химия, автор: lexatum2003

1.Сколько весят 0.25 моль питьевой соды NaHCO3 ? Пожалуйста с Дано Решение

Ответы

Автор ответа: krioira

n= 0.25 (моль)

M(NaHCO3) = 23+1+12+3*16= 84 (г/моль)
m = n*M = 0.25*84 = 21 (г)

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