Предмет: Геометрия, автор: holop1200000

точка A(-5;-1)B(1;-1) C(-2;5) найти расстояние BC,
Найти S треугольника ABC

Ответы

Автор ответа: au456
0
Вектор ВС(-3;6) его длина √((-3)^2+6^2)=√45=3√5

Вектор ВА(-6;0)

Площадь - половина модуля векторного произведения BA на ВС
1/2 | ((-6)*6-0*(-3) | = 18
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