Question

x^0,5*x^0,25=

a^2/3*a^1/6=

x^5/6*x^-0,5=

b*b^-1/2/3=

a^3/5*a^-3/5=

y^1/2*y^1/4*y^1/3=

z^2/3*z^3/4*z^5/6=

РЕШИТЕ ПОЖАЛУЙСТА:))

Answer 1

$x^{0,5}*x^{0,25}=x^{0,5+0,25}=x^{0,75}$
$a^{frac{2}{3}}*a^{frac{1}{6}}=a^{frac{2}{3}+frac{1}{6}}=a^{frac{4}{6}+frac{1}{6}}=a^{frac{5}{6}}$
$x^{frac{5}{6}}*x^{-0,5}=x^{frac{5}{6}}*x^{-frac{1}{2}} =x^{frac{5}{6}-frac{1}{2}}=x^{frac{5}{6}-frac{3}{6}}=x^{frac{2}{6}}=x^{frac{1}{3}}$
$b*b^{-1frac{2}{3}}=b^{1-1frac{2}{3}}=b^{-frac{2}{3}$
$a^{frac{3}{5}}*a^{-frac{3}{5}}=a^{frac{3}{5}-frac{3}{5}}=a^0=1$
$y^{frac{1}{2}}*y^{frac{1}{4}}*y^{frac{1}{3}}=y^{frac{1}{2}+frac{1}{4}+frac{1}{3}}=y^{frac{6}{12}+frac{3}{12}+frac{4}{12}}=y^{frac{13}{12}}$
$z^{frac{2}{3}}*z^{frac{3}{4}}*z^{frac{5}{6}}=z^{frac{2}{3}+frac{3}{4}+frac{5}{6}}=z^{frac{8}{12}+frac{9}{12}+frac{10}{12}}=z^{frac{8}{12}+frac{9}{12}+frac{10}{12}}=z^{frac{27}{12}}$