Question

Решить систему методом подстановки х+у=4 у+ху=6

Answer 1

$left { {{x+y=4} atop {y+xy=6}} right. ; ; left { {{x=4-y} atop {y+y(4-y)=6}} right. ; ; left { {{x=4-y} atop {y+4y-y^2=6}} right. ; ; left { {{x=4-y} atop {y^2-5y+6=0}} right. \\ left { {{x=4-y} atop {(y-2)(y-3)=0}} right. ; ; left { {{x_1=2; ,; x_2=1} atop {y_1=2; ,; y_2=3}} right. \\Otvet:; ; (2,2); ,; (1,3); .$