Question

Решить неравенство:
х в квадрате+6x-18<0

Answer 1

$x^2+6x-18<0 \ x^2+6x-18=0 \ D_1=9+18=27 \ x= -3pm sqrt{27} \ xin( -3-sqrt{27}; -3+sqrt{27})$

Answer 2

$x^2+6x-18<0\D=36+4cdot 18=108\x=cfrac{-6pmsqrt{108}}{2}\(x+3+3sqrt{3})(x+3-3sqrt{3})<0\xin (-3-sqrt{3};-3+3sqrt{3})$