Question

Разложите на множители: 9b^2-(b+3)^2 

Answer 1

$9b^2-(b+3)^2=(3b)^2-(b+3)^2=(3b+(b+3))(3b-(b+3))=\\(3b+b+3)(3b-b-3)=(4b+3)(2b-3)$

Answer 2

(3b)^2 - (b+3)^2=
=( 3b - b - 3)(3b + b+3)=
=(2b-3)(4b+3)