Question

Помогите пожалуйсто решить срчно...
4 и 6 задание... задания на фото

Answer 1

Ответ-----☆☆☆☆☆☆---------

Answer 2

$4)lim _{xto :0.5}left(frac{-2x^2+7x-3}{2x-1}right)=lim _{xto :0.5}left(-x+3right)=-0.5+3=2.5 \ \ \ 6)lim _{xto 3}left(frac{sqrt{2x+10}-4}{x-3}right)=\ \ frac{sqrt{2x+10}-4}{x-3}=frac{left(sqrt{2x+10}-4right)left(sqrt{2x+10}+4right)}{left(x-3right)left(sqrt{2x+10}+4right)}=frac{2x-6}{left(x-3right)left(sqrt{2x+10}+4right)}= \ =frac{2left(x-3right)}{left(x-3right)left(sqrt{2x+10}+4right)}=frac{2}{sqrt{2x+10}+4}$
$lim _{xto :3}left(frac{2}{sqrt{2x+10}+4}right)=frac{2}{sqrt{2cdot :3+10}+4}= frac{1}{4} =0,25$