Предмет: Информатика, автор: arushikir

ПОМОГИТЕ ПЖ: информационный объем текстового сообщения равен 3 кбайт. Количество символов в тексте равно 2048. Какова мощность алфавита, с помощью которого записано данное текстовое сообщение?

Ответы

Автор ответа: petyaGavrikov

0

3 Кбайта = 3*1024*8 бит
Объем одного символа = 3*1024*8 / 2048 = 12 бит
Мощность алфавита = 2^12 = 4096

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