Question

1) 4^x+1 + 4^x+2=40
2) 9^x+1 + 3^2x+4=30

Answer 1

$4^{x+1}+4^{x+2}=40\ 4^x*4+4^x*16=40\ 20*4^x=40\ 4^x=2\ x=frac{1}{2}\ 9^{x+1}+3^{2x+4}=30\ 9^x*9+9^x*81=30\ 90*9^x=30\ 9^x=frac{1}{3}\ x=-frac{1}{2}$