Question

найдите корни уравнения x-(x-32+2x²)=0

Answer 1

x-(x-32+2x²)=0
x-x+32-2x²=0
x²=32/2
x²=16
x₁=4
x₂=-4

Answer 2

$x-(x-32+2x^2)=0\ x-x+32-2x^2=0\32-2x^2=0\2(16-x^2)=0 | :2\ (4-x)(4+x)=0\ 1) 4-x=0\ x=4\2)4+x=0\x=-4$  Ответ: x=-4, x=4.