Question

Решите неравенство...

Answer 1

$dfrac{9}{x+1}- dfrac{4}{x-4} leq5\ dfrac{5(x+1)(x-4)-9(x-4)+4(x+1)}{(x-4)(x+1)}geq0 \ dfrac{5(x^2-4x+x-4)-9x+36+4x+4}{(x+1)(x-4)}geq0 \ dfrac{5x^2-20x+5x-20-9x+36+4x+4}{(x+1)(x-4)}geq0\ dfrac{5x^2-20x+20}{(x-4)(x+1)}geq0 \ boxed{left { {{5x^2-20x+20geq0} atop {(x+1)(x-4) textgreater 0}} right. }\boxed{ left { {{x^2-4x+4geq0} atop {(x-4)(x+1) textgreater 0}} right. }\boxed{ left { {{(x-2)^2geq0} atop {(x+1)(x-4) textgreater 0}} right. }\1)chisl nyl.:x=-1;x=4\2)znam. nyl.:x=2$
ответ х∈(-∞;-1);{2};(4;∞)

Answer 2

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