Question

ПООМОГИТЕ РЕШИТЬ АЛГЕБРУ ПЖ

Answer 1

$\left \{ {{4x^2+y=9} \atop {8x^2-y=3}} \right.\\ \left \{ {{12x^2=12} \atop {y=9-4x^2}} \right.\\ \left \{ {{x^2=1} \atop {y=9-4x^2}} \right.\\ \left \{ {{x=1} \atop {y=9-4*1^2}} \right.\\ \left \{ {{x=1} \atop {y=5}} \right.\\our\\ \left \{ {{x=-1} \atop {y=9-4*(-1)^2}} \right.\\ \left \{ {{x=-1} \atop {y=5}} \right.$
ответ (1;5);(-1;5)

Answer 2

{4x²+y=9
{8x²-y=3
прибавим
12x²=12
x²=1
x=-1⇒4+y=9⇒y=9-4⇒y=5
x=1⇒4+y=9⇒y=5
Ответ (-1;5);(1;5)