Question

5^1-log25 (4)-9^-log9(2)

Answer 1

$5^{1- log_{25}4 }- 9^{- log_{9}2 } = \frac{ 5^{1} }{ 5^{ log_{25}4 } } - \frac{1}{ 9^{ log_{9} 2} } = \frac{5}{ 5^{ log_{ 5^{2} }4 } }- \frac{1}{2} = \frac{5}{ 5^{ \frac{1}{2}* log_{5} 4 } } -0,5=$
$= \frac{5}{ 5^{ log_{5} 4^{ \frac{1}{2} } } } -0,5= \frac{5}{2} -0,5=2,5-0,5=2$

Answer 2

$log_{a^n}b^n=log_ab$
$5^{1-log_{25}4}-9^{-log_92}}=5/5^{log_52}-1/2=5/2-1/2=4/2=2$