Question

Решить неравенство log0,5^(x^-2)>=log2^(2x+3).
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Answer 1

Решение на фотографии

Answer 2

ОДЗ
{x≠0
{2x+3>0⇒x>-1,5
x∈(-1,5;0) U (0;∞)
log(0,5)(x^-2)=log(2)x²
log(2)x²≥log(2)(2x+3)
x²≥2x+3
x²-2x-3≥0
x1+x2=2 U x1*x2=-3
x1=-1 U x2=3
                 +                         _                             +
---------------------[-1]------------------[3]--------------------------------
x≤-1 U x≥3
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\                                          //////////////////               
----------(-1,5)----------[-1]---------------(0)-------------[3]-----------
                //////////////////////////////////////////\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
 x∈(-1,5;-1] U [3;∞)