Question

$\frac{x-1}{x+3} \ \textgreater \ 2$

Answer 1

$\frac{x-1}{x+3} \ \textgreater \ 2$
$\frac{x-1}{x+3} -2\ \textgreater \ 0$
$\frac{x-1-2*(x+3)}{x+3}\ \textgreater \ 0$
$\frac{-x-7}{x+3} \ \textgreater \ 0$ метод интервалов:
1. $\frac{-x-7}{x+3} =0 \left \{ {{x=-7} \atop {x} \neq -3} \right.$
2.  
     -             +              -  
 -------(-7)----------(-3)-------------->x

3. ответ: x∈(-7;-3)