Question

2-5tg^2x*cos^2x , если sin x=0.6

Answer 1

$sinx=0.6 \\ cosx= \sqrt{1-0.36} \\ cosx=0.8$

$tgx= \frac{sinx}{cosx}=0.6/0.8=0.75$

$2-5tg^2x*cos^2x=2-5*(0.75)^2*(0.8)^2=2-5*0.36=2-1.8= \\ =0.2$

ответ: 0.2