Question

Прошу помогите срочно

Answer 1

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Answer 2

1.
$\sqrt{x+y^2}= \sqrt{15+(-7)^2} = \sqrt{15+49}= \sqrt{64}=8$
2.
$S= \frac{ \pi d^2}{4} \\ \pi d^2= 4S \\ d^2 = \frac{4S}{\pi } \\ d= \pm \sqrt{\frac{4S}{\pi } } = \pm 2 \sqrt{\frac{S}{ \pi } }$
3.
$\sqrt{25}\ \textless \ \sqrt{26}\ \textless \ \sqrt{36}\\ 5\ \textless \ \sqrt{26}\ \textless \ 6\\ \sqrt{25}\ \textless \ \sqrt{30}\ \textless \ \sqrt{36}\\ 5\ \textless \ \sqrt{30}\ \textless \ 6$
4, 5
$\sqrt{0.64*36}= \sqrt{0.64}* \sqrt{36}=0.8*6= 4.8\\ \frac{ \sqrt{320} }{ \sqrt{80} } = \sqrt{ \frac{320}{80} } = \sqrt{4}=2$
6.
$\frac{(3* \sqrt{8} )^2}{24} = \frac{3^2*8}{24}= \frac{9}{3} =3$
7.
$2 \sqrt{12}- \sqrt{75} = 2 \sqrt{4*3}- \sqrt{25*3} =4 \sqrt{3}-5 \sqrt{3} =- \sqrt{3}$
8.
$2a^2 = 2( \sqrt{3}-1 )^2=2(( \sqrt{3} )^2-2 \sqrt{3}+1)=6-4 \sqrt{3} +2=8-4 \sqrt{3}$
9.
$\sqrt{25} \ \textless \ \sqrt{30} \ \textless \ \sqrt{36} \\ 5 \ \textless \ \sqrt{30} \ \textless \ 6 \\ 10 \ \textless \ 2\sqrt{30} \ \textless \ 12 \\ 10 \ \textless \ 2\sqrt{30}$