Question

Помогите решить срочно

Answer 1

....=((2у)² - х²)/2ху * 1/(2у+х)=((2у+х)(2у-х)) / (2ху(2у+х))=(2у-х)/2ху

при  х=1/9,  у=1/6

(2*1/6 - 1/9)/(2*1/6*1/9)=(1/3-1/9)/(1/27)=27(3/9 - 1/9)=27 * 2/9=3*2=6