Question

(x-(x/(1-x)))/(3x^4/(x^2-2x+1))  при х=1/6

Answer 1

$frac{x-frac{x}{1-x}}{frac{3x^4}{x^2-2x+1}}=frac{(x-x^2-x)(x-1)^2}{(1-x)3x^4}=frac{-x^2(x-1)^2}{-(x-1)3x^4}=frac{x-1}{3x^2}$