Question

(х^2+x+1)*(x^2+x+2)=12

Answer 1

(x²+x+1)(x²+x+2)=12=2x^4+x³+2x²+x³+x²+2x+x²+x+2=12=2x^4+x³+2x²+x³+x²+2x+x²+2=12=

=2x^4+x³+2x²+x³+x²+2x+x²=10=2x^4+2x³+4x²+2x=10