Question

$intlimits {sin^{2}3x} , dx$

Answer 1

$intlimits{ sin^2(3x) } , dx= intlimits{ frac{1-cos(6x)}{2} } , dx= intlimits{ frac{1}{2} } , dx- intlimits{ frac{cos(6x)}{2} } , dx=$$frac{x}{2}-frac{sin(6x)}{12}+C$