Question

Сократите дробь

5x^2+x-4    

/x^2+x

Answer 1

$\frac{5x^2+x-4}{x^2+x}=frac{5x^2+5x-4x-4}{x(x+1)}=frac{5x(x+1)-4(x+1)}{x(x+1)}= \. \frac{(x+1)(5x-4)}{x(x+1)}=frac{5x-4}{x}, xneq0 wedge xneq-1$