Question

Решить уравнение:
(X-3)^2+(x+4)^2-(x-5)^2=17x+24

Answer 1

$(x-3)^2+(x+4)^2-(x-5)^2=17x+24 \ x^2-6x+9+x^2+8x+16-x^2+10x-25-17x-24=0 \ x^2-5x-24=0 \ D=25+4cdot24=121 \ x_1= frac{5+11}{2}=8 \ x_1= frac{5-11}{2}=-3$
Ответ: 8 и -3

Answer 2

x^2 -6x+9+x^2+8x+16 -x^2+10x-25-17x-24 =0
x^2 -5x -24 =0
D = 25 -4(-24) =Y121;  D=11
x1= (5+11)/2 =8
x2 =(5-11)/2 = -3

Answer 3

^2 -6x+9+x^2+8x+16 -x^2+10x-25-17x-24 =0
x^2 -5x -24 =0
D = 25 -4(-24) =Y121; D=11
x1= (5+11)/2 =8
x2 =(5-11)/2 = -3