Question

f'(П/2) если f(x)=3sinxcosx

Answer 1

f`(x)=(3sinxcosx)` =   3(sinx)`*cosx+3sinx*(cosx)` = 3cosx*cosx+3sinx*(-sinx)
f`(П/2) =   3*0*0+3*1*(-1) = -3